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ManipulatingStrings
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!Two Methods For Finding The Length Of a String *test="This is a string" Method 1) *echo ${#test} Method 2) *expr length test Both will give you the correct length of 16. !How can I get a substring of a variable? Say the variable test contains the string "corndog" but we want just the "dog" part. echo ${test:4:3} will return just "dog" The 4 tells us the index of the char that will be the first char in the substring. The 3 tells us how many letters to add starting at the index. !Remove Substrings (uses bash's pattern matching) Strips *shortest* match of $substring from *front* of $string. *${string#substring} For example if $string contained "This is a string" and we replaced substring with ''T*'' an echo would result in ''his is a string'' Strips *longest* match of $substring from *front* of $string. *${string##substring} For example if $string contained "This is a string" and we replaced substring with ''T*'' an echo would result in an empty string. (The longest match was the entire string). Strips *shortest* match of $substring from *back* of $string. *${string%substring} For example if $string contained "This is a string" and we replaced substring with ''s*'' an echo would result in ''This is a'' Strips *longest* match of $substring from *back* of $string. *${string%%substring} For example if $string contained "This is a string" and we replaced substring with ''s*'' an echo would result in ''Thi'' (The longest match) !Concatenate variables. *echo ${string1}${string2} If we did: *echo $string1string2 then bash would be looking for a variable called ''string1string2'' (which does not exist). This is why the curly brackets are necessary. Another Example: *echo ${string1}"Some more Text" !Brace Expansion *echo C{a,u,o}t Will return ''Cat Cut Cot'' Another example of where this could be useful: *mkdir ~~/test/{cat,dog,rabbit} This will create a ''cat'' , ''dog'' and ''rabbit'' dir in ~~/test/
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